200以上 (1-x^2)y''+2xy'=0 y1=1 168184-Solve 0=y=(1-x^(2))y''-2xy'+1(2+1)y
After solving for this you will get x2y22x4y11=0 No solutions found Step by step solution Step 1 Equation at the end of step 1 x2 2x y2 4y 11 = 0 Step 2 Solving a Single Variable Power Series Solution of Differential Equation (x^2 1)y'' xy' y = 0 Academic Videos (Solved Examples)Use fp dx = In 1/ (1 x²) , find U with its integral to get Y2 = uyi Reduce to first order and solve (1 x2 )y" 2xy' 2y = 0, y1 = x Use fp dx = In 1/ (1 x²) , find U with its integral to get Y2 = What Is The Solution Of This Differential Equation X 2 Y 2xy 2 Dx X 3 3x 2y Dy 0 Quora Solve 0=y=(1-x^(2))y''-2xy'+1(2+1)y